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We previously examined infinite series with constant terms whose sums (when convergent) were numbers. However, series have more practical usage when the series have variable terms.
We noted before that regarding this equation:
we found:
if we were to write r = x for the ratio in a geometric series, then Theorem 1 gives us as the infinite series representation
of the function f (x) = 1/(1-x). In other words, for each fixed number x with |x| <>1/(1-x). The nth partial sum
of the geometric series in the equation above this one above is now an nth-degree polynomial that approximates the function f (x) = 1/(1 - x). The convergence of the infinite series for
should then be accurate if n is sufficiently large. The figure
Shows the graphs of 1/(1 - x) and the three approximations
It appears that the approximations are more accurate when n is larger and when x is closer to zero.
Polynomial Approximations:
Perhaps we want to calculate or approximate a specific value
of a given function f. We would only need to find a polynomial P (x) whose graph is close to the graph of f on some interval containing
Because if so, we could then use the value
as an approximation of the actual value for
Then as soon as we know how to find such an approximated polynomial P (x), we next would need to know how accurately
approximates the desired value
The simplest example of polynomial approximation is the linear approximation
which we obtained by writing
in the linear approximation formula
The graph for the first-degree polynomial
is the line tangent to the curve y = f (x) at the point (a, f (a)):
Example 2: We suppose that f (x) = ln x and that a = 0. [The ln x means 'the power which e must be raised to get x.'] Then f (1) = 0 [because when x is at point 1, y is at zero] and f ' (1) = 1 [because was determined as the value whose differential is its own value, so when e^x is made just e when x = 1, then we obtain the value for the slope that when multiplied to e obtains e again, which is 1/1]; so,
[because the polynomial takes the a value to be 1]. Hence we expect that
for x near 1 [because we are substituting the polynomial for the function producing e.] With x = 1.1, we find that
Thus the error in this polynomial approximation for ln x is about 5%.
To better approximate ln x near x = 1, we will find a second-degree polynomial
that not only has the same value and the same first derivative as does f at x = 1, but also has the same second derivative there:
In order to satisfy these conditions, we must have:
When we solve these equations we get:
so
With x = 1.1, we see that
which is accurate to three decimal places because
The graph of
is a parabola through (1,0) with the same value, slope, and curvature there as y = ln x:
The tangent line and the parabola used in the computations of this above example illustrate one general approach to polynomial approximation. To approximate the function f (x) near x = a , we look for an nth-degree polynomial
such that its value at a and the values of its first n derivatives at a agree with the corresponding values of f. That is, we require that
We can use these n + 1 conditions to evaluate the values of the n + 1 coefficients
The algebra involved is much simpler, however, if we begin with
expressed as an nth-degree polynomial in powers of x - a rather than in powers of x:
The substituting x = a in the above equation yields
[because the x's cancel to zero, leaving only the first coefficient] by the first condition of the vertical series of equations.
Next, substituting x = a into
yields
so,
[by dividing out the 2 from the left side]. We continue the process to find
In general, the constant term in the kth derivative
because it is the kth derivative of the kth-degree term
(Recall that
denotes the factorial of the positive integer k, read "k factorial"). So when we substitute x = a into
we find that
and thus that
for k = 1, 2, 3, . . . , n.
The above equation also holds for k = 0 if we use the universal convention that 0! = 1 and agree that the zeroth derivative
of the function g is just g itself. With such conventions, our computations establish the following theorem.
Theorem: The nth-Degree Taylor Polynomial:
Suppose that the first n derivatives of the function f (x) exist at x = a. Let
be the nth-degree polynomial
Then the values of
and its first n derivatives agree, at x = a, with the values of f and its first n derivatives there. That is, the equations below hold:
The polynomial in the above equation
is called the nth-degree Taylor polynomial of the function f at the point x = a. We take note that
is a polynomial in powers of x - a rather than in powers of x. To use
effectively for the approximation of f (x) near a, we must be able to compute the value f (a) and the values of its derivatives f ' (a), f '' (a), and so on, all the way to
The line
is simply the line tangent to the curve y = f (x) at the point (a, f (a)). Thus y = f (x) and
have the same slope at this point. We recall from before that the second derivative measures the way the curve y = f (x) is bending as it passes through (a, f (a)). Thus, we call f '' (a) the "concavity" of y = f (x) at (a, f (a)). Then, because
it follows that
has the same value, the same slope, and the same concavity at (a, f (a)) as does y = f (x). In addition,
and f (x) will also have the same rate of change of concavity at (a, f (a)). Such observations suggest that the larger n is, the more closely the nth-degree Taylor polynomial will approximate f (x) for x near a.
Example 3: Find the nth-degree Taylor polynomial of f (x) = 1
The pattern is clear:
hence
so the equation
gives
With n = 2 we obtain the quadratic polynomial:
which is the same as from our previous example. With the third-degree Taylor polynomial
we can go a step further in approximating
The value
is accurate to four decimal places (rounded). In the figure below
we see that the higher the degree and the closer x is to 1, the more accurate the approximation
appears to be.
In the common case a = 0, the nth-degree Taylor polynomial in equation
reduces to
Example 4: Find the nth-degree Taylor polynomial for
This is the easiest of all Taylor polynomials to compute, because
for all
Thus the equation
yields
[by using the nth-Degree Taylor Polynomial theorem:
]. The first few Taylor polynomials of the natural exponential function at a = 0 are, therefore,
The figure below shows the graphs of
The table below shows how these polynomial approximate
for x = 0.1 and for x = 0.5.
At least for these two values of x, the closer x is to a = 0, the more rapidly
appears to approach f (x) as n increases.
Taylor's Formula:
The closeness with which the polynomial
approximates the function f (x) is measure by the difference
for which
This difference
is called the nth-degree remainder for f (x) at x = a. It is the error made if the value f (x) is replaced with the approximation
The theorem that lets us estimate the error, or remainder,
is called Taylor's formula, after Brook Taylor (1685-1731), a follower of Newton who introduced Taylor polynomials in an article published in 1715. The particular expression for
that we give next is called the Lagrange form for the remainder because it first appeared in 1797 in a book by the French mathematician Joseph Louis Lagrange (1936-1813).
Theorem 2: Taylor's Formula:
Suppose that the (n + 1)th derivative of the function f exists on an interval containing the points a and b. Then
for some number z between a and b.
If we replace b with x in the above equation, we get the nth-degree Taylor formula with remainder at x = a:
where z is some number between a and x. Thus the nth-degree remainder term is
[because it is the last term in the series].
Example 3 continued: Estimate the accuracy of the approximation
we substitute x = 1 into the formula
for the kth derivative of f (x) = ln x and get
Hence the third-degree Taylor formula with remainder at x = 1 is
with z between a = 1 and x. With x = 1.1 this gives
where 1 <>z = 1 gives the largest possible magnitude
[more clearly: (0.1)^4/4 = 0.000025] of the remainder term. It follows that
o.095308 <>
so we can conclude that ln(1.1) = 0.0953 to four-place accuracy.
Taylor Series:
If the function f has derivatives of all orders, then we can write Taylor's formula [Suppose that the (n + 1)th derivative of the function f exists on an interval containing the points a and b. Then
for some number z between a and b.] with any degree n that we please. Ordinarily, the exact value of z in the Taylor remainder term in equation
is unknown. Nevertheless, we can sometimes use this equation to show that the remainder approaches zero as
for some particular fixed value of x. Then the equation
gives:
[because
]; that is,
The infinite series:
is called the Taylor Series of the function f at x = a. Its partial sums are the successive Taylor polynomials of f at x = a.
We can write the Taylor series of a function f without knowing that it converges. But if the limit in equation
can be established, then it follows as in equation
that the Taylor Series in equation
actually converges to f (x). If so, then we can approximate the value of f (x) sufficiently accurately by calculating the value of a Taylor polynomial of f of sufficiently high degree.
Example 5: In example 4 we noted that if
for all integers
Hence the Taylor formula
at a = 0 gives
for some z between 0 and x. If x and hence z are negative then
if both are positive. Thus the remainder term
satisfies the inequalities
Therefore, the fact that
for all x implies that
for all x. This means that the Taylor series for
converges to
for all x, and we may write
The series in this above equation is the most famous and most important of all Taylor series. With x = 1, the above equation yields a numerical series
for the number e itself. The 10th and 20th partial sums of this series give the approximations
both of which are accurate to the number of decimal places shown.
from Edwards & Penney: Calculus. New Jersey: Prentice Hall, 2002, p.702a-709c.
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